\( 22.7 \mathrm{~mL} \) of \( (\mathrm{N} / 10) \mathrm{Na}_{2} \mathrm{CO}_{3} \) solution neut...
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0\( 22.7 \mathrm{~mL} \) of \( (\mathrm{N} / 10) \mathrm{Na}_{2} \mathrm{CO}_{3} \) solution neutralises \( 10.2 \mathrm{~mL} \) of a dilute \( \mathrm{H}_{2} \mathrm{SO}_{4} \) solution. The volume of water that must be added to \( 400 \mathrm{~mL} \) of this \( \mathrm{H}_{2} \mathrm{SO}_{4} \) solution in order to make it exactly \( \mathrm{N} / 10 \).
(1) \( 490.2 \mathrm{~mL} \)
(2) \( 890.2 \mathrm{~mL} \)
(3) \( 90.2 \mathrm{~mL} \)
(4) \( 290.2 \mathrm{~mL} \)
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