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\( A B C D \) is a trapezium, such that \( A B \) and \( C D \) are parallel \( B C \perp C D \). If \( \angle A D B=\theta, B C=p \) and \( C D=q \), then \( A B \) is equal to
(a) \( \frac{\left(p^{2}+q^{2}\right) \sin \theta}{p \cos \theta+q \sin \theta} \)
(b) \( \frac{p^{2}+q^{2} \cos \theta}{p \cos \theta+q \sin \theta} \)
(c) \( \frac{p^{2}+q^{2}}{p^{2} \cos \theta+q^{2} \sin \theta} \)
(d) \( \frac{\left(p^{2}+q^{2}\right) \sin \theta}{(p \cos \theta+q \sin \theta)^{2}} \)
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