A block lying on a long horizontal conveyor belt moving at a constant velocity receives a veloci...

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A block lying on a long horizontal conveyor belt moving at a constant velocity receives a velocity \( 5 \mathrm{~m} / \mathrm{s} \) at \( t=0 \mathrm{sec} \). relative to the ground in the direction opposite to the direction of motion of the conveyor. After \( t=4 \mathrm{sec} \), the velocity of the block becomes equal to the velocity of the belt. The coefficient of friction between the block and the belt is 0.2 . Then the velocity of the conveyor belt is: \( \left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right) \)
(a) \( 13 \mathrm{~m} / \mathrm{s} \)
(b) \( -13 \mathrm{~m} / \mathrm{s} \)
(c) \( 3 \mathrm{~m} / \mathrm{s} \)
(d) \( 6 \mathrm{~m} / \mathrm{s} \)
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