Duration: 2:48

50 views

0

A block of base \( 10 \mathrm{~cm} \times 10 \mathrm{~cm} \) and height \( 15 \mathrm{~cm} \) is kept on an inclined plane. The coefficient of friction between
\( \mathrm{P} \) them is 3. The inclination \( \theta \) of this inclined plane from the

W horizontal plane is gradually increased from \( 0^{\circ} \). Then
FBD at just toppling condition
(1) at \( \theta=30^{\circ} \), the block will start sliding down the plane
(2) the block will remain at rest on the plane up to certain \( \theta \) and then it will topple
(3) at \( \theta=60^{\circ} \), the block will start sliding down the plane and continue to do so at higher angles
(4) at \( \theta=60^{\circ} \), the block will start sliding down the plane and on further increasing \( \theta \), it will topple at certain \( \theta \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live