A block of mass \( m \) lies on wedge of mass \( M \). The wedge in turn lies on smooth horizont....
0A block of mass \( m \) lies on wedge of mass \( M \). The wedge in turn lies on smooth horizontal surface. Friction is absent everywhere. The wedge block system is released from rest. All situation given in column-I are to be estimated in duration the block undergoes a vertical displacement ' \( h \) ' starting from rest (assume the block to be still on the wedge, \( g \) is acceleration due to gravity).
\begin{tabular}{|l|l|l|l|}
\hline & Column-I & Column-II \\
\hline A & \begin{tabular}{l}
Work done by \\
normal reaction \\
acting on the block \\
is
\end{tabular} & P & Positive \\
\hline B & \begin{tabular}{l}
Work done by \\
normal reaction \\
(exerted by block) \\
on wedge is
\end{tabular} & Q & Negative \\
\hline C & \begin{tabular}{l}
The sum of work \\
done by normal \\
reaction on block \\
and work done by \\
normal reaction \\
(exerted by block) \\
on wedge is
\end{tabular} & \( R \) & Zero \\
\hline D & \begin{tabular}{l}
Net work done by \\
all forces on block \\
is
\end{tabular} & S & \begin{tabular}{l}
Less than \\
mgh in \\
magnitude
\end{tabular} \\
\hline
\end{tabular}
W.
W.
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live