A body is projected vertically upward with speed \( 40 \mathrm{~m} ...

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A body is projected vertically upward with speed \( 40 \mathrm{~m} / \mathrm{s} \). The distance travelled by body in the last
\( \mathrm{P} \) second of upward journey is [take \( g=9.8 \mathrm{~m} / \mathrm{s}^{2} \) and

W neglect effect of air resistance]
(1) \( 4.9 \mathrm{~m} \)
(2) \( 9.8 \mathrm{~m} \)
(3) \( 12.4 \mathrm{~m} \)
(4) \( 19.6 \mathrm{~m} \)
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