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A cannon on a level plane is aimed at an angle \( \theta \) above the horizontal and a shell is fired with a muzzle velocity \( v_{0} \) towards a vertical cliff a distance \( D \) away. Then the height from the bottom at which the shell strikes the side walls of the cliff is
(1) \( D \sin \theta-\frac{g D^{2}}{2 v_{0}^{2} \sin ^{2} \theta} \)
(2) \( D \cos \theta-\frac{g D^{2}}{2 v_{0}^{2} \cos ^{2} \theta} \)
(3) \( D \tan \theta-\frac{g D^{2}}{2 v_{0}^{3} \cos ^{2} \theta} \)
(4) \( D \tan \theta-\frac{g D^{2}}{2 v_{0}^{2} \sin ^{2} \theta} \)
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