A circle of radius 2 units passes through the vertex and the focus of the parabola \( y^{2}=2 x ... VIDEO
A circle of radius 2 units passes through the vertex and the focus of the parabola \( y^{2}=2 x \) and touches the parabola \( y=\left(x-\frac{1}{4}\right)^{2}+\alpha \), where \( \alpha0 \). Then \( (4 \alpha-8)^{2} \) is equal to
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