A force \( F=20+10 y \) acts on a particle in \( y \)-direction where \( F \) is in newton and \...
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A force \( F=20+10 y \) acts on a particle in \( y \)-direction where \( F \) is in newton and \( y \) in meter. Work done by this force to move the particle from \( y=0 \) to \( y=1 \mathrm{~m} \) is [NEET 2019]
(a) \( 20 \mathrm{~J} \)
(b) \( 30 \mathrm{~J} \)
(c) \( 5 \mathrm{~J} \)
(d) \( 25 \mathrm{~J} \)
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