A force \( \mathbf{F}=(3 x \hat{\mathrm{i}}+4 \hat{\mathrm{j}}) \) ...
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A force \( \mathbf{F}=(3 x \hat{\mathrm{i}}+4 \hat{\mathrm{j}}) \) Newton (where \( \mathrm{x} \) is in metres) acts on a particle which moves from a position \( (2 \mathrm{~m} \),
\( \mathrm{P} \) \( 3 \mathrm{~m}) \) to \( (3 \mathrm{~m}, 0 \mathrm{~m}) \). Then the work done is
W
(1) \( 7.5 \mathrm{~J} \)
(2) \( -12 \mathrm{~J} \)
(3) \( -4.5 \mathrm{~J} \)
(4) \( +4.5 \mathrm{~J} \)
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