A force \( \vec{F}=(3.00 \mathrm{~N}) \hat{\mathrm{i}}+(7.00 \mathrm{~N}) \hat{\mathrm{j}}+(7.00...
Channel:
Subscribers:
511,000
Published on ● Video Link: https://www.youtube.com/watch?v=PkNLecf2D_c
A force \( \vec{F}=(3.00 \mathrm{~N}) \hat{\mathrm{i}}+(7.00 \mathrm{~N}) \hat{\mathrm{j}}+(7.00 \mathrm{~N}) \hat{\mathrm{k}} \) acts on a \( 2.00 \mathrm{~kg} \) mobile object that moves from an initial position of \( \vec{d}_{i}=(3.00 \mathrm{~m}) \hat{\mathrm{i}}-(2.00 \mathrm{~m}) \hat{\mathrm{j}}+(5.00 \mathrm{~m}) \hat{\mathrm{k}} \) to a final position of \( \vec{d}_{f}=-(5.00 \mathrm{~m}) \hat{\mathrm{i}}+(4.00 \mathrm{~m}) \hat{\mathrm{j}}+(7.00 \mathrm{~m}) \hat{\mathrm{k}} \) in \( 4.00 \mathrm{~s} \). Find the angle between vectors \( \vec{d}_{i} \) and \( \vec{d}_{f} \).
ЁЯУ▓PW App Link - https://bit.ly/YTAI_PWAP
ЁЯМРPW Website - https://www.pw.live