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A liquid flows through a horizontal tube as shown in the figure. The velocities of the liquid in the two sections, which have areas of cross section \( A_{1} \) and \( A_{2} \), are \( v_{1} \) and \( v_{2} \), respectively. The difference in the levels of the liquid in the two vertical tubes is \( h \). Therefore,
(A) the volume of the liquid flowing through the tube in unit time is \( A_{1} Y_{1^{\circ}} \)
(B) \( v_{2}-v_{1}=\sqrt{2 g h} \)
(C) \( v_{2}^{2}-v_{1}^{2}=2 g h \).
(D) the energy per unit mass of the liquid is the same in both sections of the tube.
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