A liquid in a beaker has temperature \( \theta(t) \) at time \( t \) and \( \theta_{0} \) is tem...
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A liquid in a beaker has temperature \( \theta(t) \) at time \( t \) and \( \theta_{0} \) is temperature of surroundings, then according to Newton's law of cooling, the correct graph between \( \log _{e}\left(\theta-\theta_{0}\right) \) and \( t \) is
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