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A mass \( m \) hangs from the rim of a wheel of radius \( r \) when released from rest, the mass falls through a height \( \mathrm{h} \) in t seconds. The moment of inertia of the wheel will be-
(1) \( \frac{m(g-2 h)}{2 h}\left(\frac{r^{2}}{t^{2}}\right) \)
(2) \( \frac{m r^{2}(g-2 h) t}{2 h} \)
(3) \( \frac{m\left(g t^{2}-2 h\right) r^{2}}{2 h} \)
(4) \( \frac{m\left(g t^{2}-2 h\right) t^{2}}{2 h r^{2}} \)
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