A particle executes linear simple harmonic motion with an amplitude of \( 3 \mathrm{~cm} \). Whe...

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A particle executes linear simple harmonic motion with an amplitude of \( 3 \mathrm{~cm} \). When the particle is at \( 2 \mathrm{~cm} \) from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is
(a) \( \frac{\sqrt{5}}{\pi} \)
(b) \( \frac{\sqrt{5}}{2 \pi} \)
(c) \( \frac{4 \pi}{\sqrt{5}} \)
(d) \( \frac{2 \pi}{\sqrt{3}} \)
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