A particle is projected from level ground. Assuming projection poin...
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A particle is projected from level ground. Assuming projection point as origin, \( x \)-axis along horizontal and \( y \)-axis along vertically upwards. If particle moves in \( x \)-y plane and its path is given by \( y=a x-b x^{2} \) where \( a, b \) are positive constants. Then match the physical quantities given in column-I with the values given in column-II. ( \( \mathrm{g} \) in column II is acceleration due to gravity.)
Column I
Column II
(A) Horizontal component of velocity
(p) \( a / b \)
(B) Time of flight
(q) \( \frac{a^{2}}{4 b} \)
(C) Maximum height
(r) \( \sqrt{\frac{g}{2 b}} \)
(D) Horizontal range
(s) \( \sqrt{\frac{2 a^{2}}{b g}} \)
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