A particle is projected from point \( A \) on plane \( A B \), so
P... VIDEO
A particle is projected from point \( A \) on plane \( A B \), so
P that \( A B=\frac{2 u^{2} \tan \theta}{g \sqrt{3}} \) in the figure as shown. If \( u \) is the
W velocity of projection, find angle \( \theta \).
(1) \( 30^{\circ} \)
(2) \( 60^{\circ} \)
(3) \( 90^{\circ} \)
(4) \( 45^{\circ} \)
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