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A particle moving in a circle of radius \( \mathrm{R} \) with a uniform speed takes a time \( \mathrm{T} \) to complete one revolution.
P
If this particle were projected with the same speed at an angle ' \( q \) '
W) to the horizontal, the maximum height attained by it equals \( 4 \mathrm{R} \). The angle of projection, \( q \), is then given by:
(2021)
(a) \( \theta=\cos ^{-1}\left(\frac{\pi^{2} \mathrm{R}}{\mathrm{gT}^{2}}\right)^{1 / 2} \)
(b) \( \theta=\sin ^{-1}\left(\frac{\pi^{2} \mathrm{R}}{\mathrm{gT}}\right)^{1 / 2} \)
(c) \( \theta=\sin ^{-1}\left(\frac{2 g \mathrm{~T}^{2}}{\pi^{2} \mathrm{R}}\right)^{1 / 2} \)
(d) \( \theta=\cos ^{-1}\left(\frac{\mathrm{gT}^{2}}{\pi^{2} \mathrm{R}}\right)^{1 / 2} \)
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