A point \( A(2,1) \) is outside the circle \( x^{2}+y^{2}+2 g x+2 f...
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1A point \( A(2,1) \) is outside the circle \( x^{2}+y^{2}+2 g x+2 f y+C=0 \& A P, A Q \) are tangents to the circle.
\( \mathrm{P} \) The equation of the circle circumscribing the triangle \( A P Q \) is :
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(A) \( (x+g)(x-2)+(y+f)(y-1)=0 \)
(B) \( (x+g)(x-2)-(y+f)(y-1)=0 \)
(C) \( (x-g)(x+2)+(y-f)(y+1)=0 \)
(D) \( (x-g)(x-2)+(y-f)(y-1)=0 \)
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