Duration: 6:00

1 views

0

A quantity of \( 100.0 \mathrm{~mL} \) of \( 0.5 \mathrm{M} \mathrm{HCl} \) is mixed
P with \( 100.0 \mathrm{~mL} \) of \( 0.5 \mathrm{M} \mathrm{NaOH} \) in a constant

W pressure calorimeter with heat capacity of \( 335 \mathrm{~J} /{ }^{\circ} \mathrm{C} \). Initially \( \mathrm{NaOH} \) and \( \mathrm{HCl} \) are \( 22.50^{\circ} \mathrm{C} \) and final temperature of the mixed solution is \( 24.90^{\circ} \mathrm{C} \). Calculate the heat change for the neutralization reaction.
\[
\mathrm{NaOH}(\mathrm{aq})+\mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{NaCl}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(1)
\]
Assume densities of solution is \( 100 \mathrm{~g} \mathrm{~mL}^{-1} \) and specific heats of the solution \( 4.184 \mathrm{~J} / \mathrm{g}^{\circ} \mathrm{C} \).
Also calculate heat of neutralization
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live