A small bulb is placed at the bottom of a tank containing water to a depth of \( \sqrt{7} \mathr...
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A small bulb is placed at the bottom of a tank containing water to a depth of \( \sqrt{7} \mathrm{~m} \). The refractive index of water is \( \frac{4}{3} \). The area of the surface of water through which light from the bulb can emerge out is \( x \pi \mathrm{m}^{2} \). The value of \( x \) is
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