A spring-block system is resting on a frictionless floor as shown in the figure. The spring cons...
0A spring-block system is resting on a frictionless floor as shown in the figure. The spring constant is \( 2.0 \mathrm{~N} \mathrm{~m}^{-} \) 1 and the mass of the block is \( 2.0 \mathrm{~kg} \). Ignore the mass
P of the spring. Initially the spring is in an unstretched
W condition. Another block of mass \( 1.0 \mathrm{~kg} \) moving with a speed of \( 2.0 \mathrm{~m} \mathrm{~s}^{-1} \) collides elastically with the first block. The collision is such that the \( 2.0 \mathrm{~kg} \) block does not hit the wall. The distance, in metres, between the two blocks when the spring returns to its unstretched position for the first time after the collision is
[JEE Advanced - \( \overline{2018} \) ]
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live