Duration: 4:52

46 views

0

A steady current \( i \) flows in a small square loop of wire of side \( L \) in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let \( \mu_{1} \) and \( \mu_{2} \) respectively denote the magnetic moments due to the current loop before and after folding. Then,
(a) \( \mu_{2}=0 \)
(b) \( \mu_{1} \) and \( \mu_{2} \) are in the same direction
(c) \( \frac{\left|\mu_{1}\right|}{\left|\mu_{2}\right|}=\sqrt{2} \)
(d) \( \frac{\left|\mu_{1}\right|}{\left|\mu_{2}\right|}=\left(\frac{1}{\sqrt{2}}\right) \)
W
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live