A train of mass \( m \) moves with a velocity \( v \) on the equator from east to west. If \( \o...

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A train of mass \( m \) moves with a velocity \( v \) on the equator from east to west. If \( \omega \) is the angular
P speed of earth about its axis and \( R \) is the radius of the earth, then the normal reaction acting on the train is
W
(a) \( m g\left[1-\frac{(\omega R-2 v) \omega}{g}-\frac{v^{2}}{R g}\right] \)
(b) \( m g\left[1-2 \frac{(\omega R-v) \omega}{g}-\frac{v^{2}}{R g}\right] \)
(c) \( m g\left[1-\frac{(\omega R+2 v) \omega}{g}-\frac{v^{2}}{R g}\right] \)
(d) \( m g\left[1-2 \frac{(\omega R-v) \omega}{g}-\frac{v^{2}}{R g}\right] \)
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