Amount of Time for Binary Tree to Be Infected | Using DFS | One Pass | Leetcode 2385

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This is the 35th Video on our playlist "Binary Tree : Popular Interview Problems".
In this video we will try to understand a very good Binary Tree Problem - "Amount of Time for Binary Tree to Be Infected" ( Leetcode 2385 )
We have already solved this using BFS in this video - https://www.youtube.com/watch?v=JIlQvhrKuAk

I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.

Problem Name : Amount of Time for Binary Tree to Be Infected
Company Tags : AMAZON
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Tree/Amount%20of%20Time%20for%20Binary%20Tree%20to%20Be%20Infected.cpp
Leetcode Link : https://leetcode.com/problems/amount-of-time-for-binary-tree-to-be-infected/


My DP Concepts Playlist : https://youtu.be/7eLMOE1jnls
My Graph Concepts Playlist : https://youtu.be/5JGiZnr6B5w
My GitHub Repo for interview preparation : https://github.com/MAZHARMIK/Interview_DS_Algo
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Approach Summary : The approach utilizes a recursive depth-first traversal of the binary tree. The "traverse" function calculates the depth of each subtree and updates the maximum distance based on certain conditions. The "amountOfTime" function initiates the traversal with the root of the binary tree and the specified starting node value. The final result returned is the maximum distance from the starting node value to any leaf node in the tree.

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✨ Timelines✨
00:00 - Introduction

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