An electron moving with the speed \( 5 \times 10^{6} \mathrm{~m} \) per sec is shooted parallel ...
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An electron moving with the speed \( 5 \times 10^{6} \mathrm{~m} \) per sec is shooted parallel to the electric field of intensity \( 1 \times 10^{3} \mathrm{~N} / \mathrm{C} \). Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of \( e=9 \times 10^{-31} \mathrm{Kg} \). charge \( =1.6 \times 10^{-19} \mathrm{C} \) )
(a) \( 7 m \)
(b) \( 0.7 \mathrm{~mm} \)
(c) \( 7 \mathrm{~cm} \)
(d) \( 0.7 \mathrm{~cm} \)
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