An ideal massless spring \( S \) can be compressed \( 1.0 \mathrm{~m} \) in equilibrium by a for...

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An ideal massless spring \( S \) can be compressed \( 1.0 \mathrm{~m} \) in equilibrium by a force of \( 100 \mathrm{~N} \). This same spring is placed at the bottom of a friction less inclined plane which makes an angle \( \theta=30^{\circ} \) with the horizontal. A \( 10 \mathrm{~kg} \) mass \( m \) is released from the rest at the top of the inclined plane and is brought to rest momentarily after compressing the spring by \( 2.0 \mathrm{~m} \). The distance through which the mass moved before coming to rest is
(a) \( 8 \mathrm{~m} \)
(b) \( 6 \mathrm{~m} \)
(c) \( 4 \mathrm{~m} \)
(d) \( 5 \mathrm{~m} \)
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