An object is projected with a velocity of \( 20 \mathrm{~m} / \mathrm{s} \) making an angle of \...

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An object is projected with a velocity of \( 20 \mathrm{~m} / \mathrm{s} \) making an angle of \( 45^{\circ} \) with horizontal. The equation for the trajectory is \( h=A x-B x^{2} \) where \( h \) is height, \( x \) is horizontal distance, \( A \)
[EAMCET 2001]
(a) \( 1: 5 \)
(b) \( 5: 1 \)
(c) \( 1: 40 \)
(d) \( 40: 1 \)
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