Assume end correction approximately equals to \( (0.3) \times( \) d...

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Assume end correction approximately equals to \( (0.3) \times( \) diameter of tube), estimate the approximate number
\( \mathrm{P} \) of moles of air present inside the tube (Assume tube is at NTP, and at NTP, \( 22.4 \) litre contains 1 mole)
(a) \( \frac{10 \pi}{36 \times 22.4} \)
(b) \( \frac{10 \pi}{18 \times 22.4} \)
(c) \( \frac{10 \pi}{72 \times 22.4} \)
(d) \( \frac{10 \pi}{60 \times 22.4} \)
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