Calculate the acceleration due to gravity on the surface of a pulsar of mass \( M=1.98 \times 10...

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Calculate the acceleration due to gravity on the surface of a pulsar of mass \( M=1.98 \times 10^{30} \mathrm{~kg} \) and radius \( R=12 \mathrm{~km} \) rotating with time period \( T=0.041 \) seconds
\[
\left(\mathrm{G}=6.67 \times 10^{-11} \mathrm{MKS}\right)
\]
[AMU (Engg.) 2012]
(a) \( 9.2 \times 10^{11} \mathrm{~m} / \mathrm{s}^{2} \)
(b) \( 8.15 \times 10^{11} \mathrm{~m} / \mathrm{s}^{2} \)
(c) \( 7.32 \times 10^{11} \mathrm{~m} / \mathrm{s}^{2} \)
(d) \( 6.98 \times 10^{11} \mathrm{~m} / \mathrm{s}^{2} \)
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