Comprehension: The first ionization energy of \( \mathrm{Na}, \mathrm{NO}, \mathrm{Xe} \), and \...

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Comprehension:
The first ionization energy of \( \mathrm{Na}, \mathrm{NO}, \mathrm{Xe} \), and \( \mathrm{O}_{2} \) follows the order \( \mathrm{Na}\mathrm{NO}\mathrm{Xe}=\mathrm{O}_{2} \cdot \mathrm{O}_{2} \) reacts with the powerful oxidizing agent \( \mathrm{PtF}_{6} \) to yield a compound \( \mathrm{O}_{2}\left[\mathrm{Pt} \mathrm{F}_{6}\right] \).

The oxidation state of \( \mathrm{Xe} \) in \( \mathrm{Xe}\left[\mathrm{PtF}_{6}\right] \) is:
(a) \( +1 \)
(b) \( +2 \)
(c) \( +4 \)
(d) \( +6 \)
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