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Consider a compound slab consisting of two pieces of same length and different materials having equal thicknesses and thermal conductivities \( K \) and \( 2 K \), respectively. The equivalent thermal conductivity of the slab is
(1) \( 2 / 3 \mathrm{~K} \)
(2) \( \sqrt{2} \mathrm{~K} \)
(3) \( 3 \mathrm{~K} \)
(4) \( 4 / 3 \mathrm{~K} \)
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