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Consider a fusion reaction \( { }^{4} \mathrm{He}+{ }^{4} \mathrm{He}={ }^{8} \mathrm{Be} \). For the reaction \( \mathrm{Q} \)-value is \( -(90+\mathrm{n}) \mathrm{KeV} \). Find \( \mathrm{n} \). Take \( 1 \mathrm{amu}=\frac{930}{\mathrm{c}^{2}} \mathrm{MeV} \). Atomic mass of \( { }^{8} \mathrm{Be} \) is \( 8.0053 \mathrm{u} \) and that of \( { }^{4} \mathrm{He} \) is \( 4.0026 \mathrm{u} \).
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