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Consider the word \( \mathrm{W}= \) MISSISSIPPI If the number of arrangements of the letters of the word W if all the S's and P's are separated is \( (\mathrm{K})\left(\frac{10 !}{4 ! \cdot 4 !}\right) \)
\( \mathrm{P} \) then \( \mathrm{K} \) equals

W
(A) \( \frac{6}{5} \)
(B) 1
(C) \( \frac{4}{3} \)
(D) \( \frac{3}{2} \)
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