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Correct set of quantum numbers defining the
\( \mathrm{P} \) highest energy electron in scandium (I) ion is

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(A) \( \mathrm{n}=3, l=1, \mathrm{~m}=0, \mathrm{~s}=-1 / 2 \)
(B) \( \mathrm{n}=3, l=0, \mathrm{~m}=0, \mathrm{~s}=-1 / 2 \)
(C) \( \mathrm{n}=4, l=0, \mathrm{~m}=0, \mathrm{~s}=+1 / 2 \)
(D) \( \mathrm{n}=3, l=2, \mathrm{~m}=2, \mathrm{~s}=+1 / 2 \).
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