Count Subarrays of Length Three With a Condition | Easy | Leetcode 3392 | codestorywithMIK
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Hi Everyone, this is the 81st video of our Playlist "Leetcode Easy".
Now we will be solving an easy array problem - Count Subarrays of Length Three With a Condition | Simple Simulation | Leetcode 3392 | codestorywithMIK
We will solve it using a simple simulation and we will do a simple dry run.
Problem Name : Count Subarrays of Length Three With a Condition | Simple Simulation | Leetcode 3392 | codestorywithMIK
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My solutions on Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/Arrays/Leetcode Easy/Count Subarrays of Length Three With a Condition.cpp
Leetcode Link : https://leetcode.com/problems/count-subarrays-of-length-three-with-a-condition
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Video Summary :
The approach involves iterating through the array and examining each subarray of length three. For each such subarray centered at index i, the condition (nums[i - 1] + nums[i + 1]) * 2 == nums[i] is checked. This condition ensures that the middle element is exactly twice the average of its neighboring elements. If the condition holds, a counter is incremented.
✨ Timelines✨
00:00 - Introduction
0:21 - Motivation
1:12 - Problem Explanation
3:10 - Simple straight forward approach + Dry Run
6:00 - Coding it up
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