Number of Equivalent Domino Pairs | Multiple Approaches | Dry Run | Leetcode 1128 | codestorywithMIK
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Hi Everyone, this is the 84th video of our Playlist "Leetcode Easy".
Now we will be solving an easy Map Based Problem - Number of Equivalent Domino Pairs | Multiple Approaches | Complete Dry Run | Leetcode 1128 | codestorywithMIK
I will explain it in full detail so that it becomes easy to understand. We will find the reason behind everything so that we understand why we did what we did.
And we will do a complete dry run
Problem Name : Number of Equivalent Domino Pairs | Multiple Approaches | Complete Dry Run | Leetcode 1128 | codestorywithMIK
Company Tags : will update later
Code Github(C++ & JAVA) - https://github.com/MAZHARMIK/Interview_DS_Algo/blob/master/HashMap/Leetcode Easy/Number of Equivalent Domino Pairs.cpp
Leetcode Link : https://leetcode.com/problems/number-of-equivalent-domino-pairs
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Video Summary :
Approach 1 (Using Map of Pairs):
Treat each domino as a sorted pair (min, max) to account for equivalence regardless of order.
Use a map to count how many times each normalized domino appears, then compute combinations using nC2.
Approach 2 (Using Frequency Array):
Exploit the fact that domino values range from 1 to 9, so each normalized pair (a, b) can be uniquely mapped to a*10 + b.
Use a fixed-size array for fast counting and incrementally add to the result as duplicates are found.
✨ Timelines✨
00:00 - Introduction
0:09 - Motivation
0:40 - Problem Explanation
3:35 - Approach-1 Brute Force
5:32 - Approach-2 Using map of pair of (int, int)
9:00 - Approach-3 Using map of strings
10:48 - Approach-4 Using constant sized vector
21:28 - Coding it up
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