Daily Practice Questions (Part-8)- Light: Reflection And Refraction | Class 10 Physics 2022-23

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Published on September 9, 2020 5:21:02 AM ● Video Link: https://www.youtube.com/watch?v=fsMhFfsUfxU

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✅ In this video,

✔️ Class: 10th
✔️ Subject: Physics
✔️ Chapter: Light: Reflection And Refraction
✔️ Topic Name: Daily Practice Questions (Part 8) - Light: Reflection And Refraction | Class 10 Physics Chapter 10 (2022-23)
✔️ Topics Covered In This Video (by Vibhuti Ma'am): In this educational video, Vibhuti Mam explains the concepts of light reflection and refraction for students in Class 10 Science. She takes a deep dive into the topics by discussing important points like angles of incidence, angles of reflection and refraction for students to understand the key concepts. She then takes up several practice questions to explain the concepts in detail. This video is perfect for the students preparing for their 2022-23 CBSE board examinations.
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00:00 Introduction: Light: Reflection And Refraction
00:06 Daily Practice Questions
39:09 Website Overview
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Points covered in this video:-

Daily Practice Questions -
1. The image obtained with a convex lens is erect and its length is 4 times the length of the object. If the focal length of the lens is 20 cm, calculate the object and image distances.

Solution. Here,
m = v/u = 4 or v = 4u, f = 20 cm, u = ?, v = ?
As, 1/v - 1/u = 1/f, 1/4u - 1/u = 1/20
(1 - 4)/4u = 1/20
4u = -60 or u = -15 cm
And
u = 4u = 4 (-15) = -60 cm.

2. We wish to obtain an equal sized inverted image of a candle flame on a screen kept at a distance of 4 m from the candle flame.
I. name the type of lens that should be used.
II. What should be the focal length of the lens and to which distance from the candle flame should the lens be placed?
III. Draw a labelled diagram to show the image formation in this case.

Solution.
a. To obtain the inverted image of a candle flame on a screen, we have to use a convex lens.
b. f = ?, u = ?
As image is of same image as the object, therefore v = u
And, v + u = 4 metre
v = u = 4/2 = 2 m
From 1/f = 1/v - 1/u = 1/2 - 1/-2 = 1; f = 1 metre
The lens has to placed at a distance of 2 m from the candle flame

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