de-Broglie wavelength of electron in second orbit of \( \mathrm{Li}^{2+} \) ion will be equal to...

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de-Broglie wavelength of electron in second orbit of \( \mathrm{Li}^{2+} \) ion will be equal to de-Broglie of wavelength of electron in:
(a) \( \mathrm{n}=3 \) of \( \mathrm{H} \)-atom
(b) \( \mathrm{n}=4 \) of \( \mathrm{C}^{5+} \) ion
(c) \( \mathrm{n}=6 \) of \( \mathrm{Be}^{3+} \) ion
(d) \( \mathrm{n}=3 \) of \( \mathrm{He}^{+} \)ion
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