Differential equations are solved by reducing them to the exact differential of an expression in...
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0Differential equations are solved by reducing them to the exact differential of an expression in \( \mathrm{x} \& \mathrm{y} \) i.e., they are reduced
P to the form \( d(f(x, y))=0 \)
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The general solution of \( \left(2 x^{3}-x y^{2}\right) d x+\left(2 y^{3}-x^{2} y\right) d y=0 \) is
(a) \( x^{4}+x^{2} y^{2}-y^{4}=c \)
(b) \( x^{4}-x^{2} y^{2}+y^{4}=c \)
(c) \( x^{4}-x^{2} y^{2}-y^{4}=c \)
(d) \( \mathrm{x}^{4}+\mathrm{x}^{2} \mathrm{y}^{2}+\mathrm{y}^{4}=\mathrm{c} \)
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