Differential equations are solved by reducing them to the exact differential of an expression in...
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Differential equations are solved by reducing them to the exact differential of an expression in \( x \) \& y i.e., they are reduced
P to the form \( \mathrm{d}(\mathrm{f}(\mathrm{x}, \mathrm{y}))=0 \)
IV
General solution of the differential equation \( \frac{x d y}{x^{2}+y^{2}} \)
\( +\left(1-\frac{y}{x^{2}+y^{2}}\right) d x=0 \) is
(a) \( \mathrm{x}+\tan ^{-1}\left(\frac{y}{x}\right)=\mathrm{c} \)
(b) \( \mathrm{x}+\tan ^{-1} \frac{x}{y}=\mathrm{c} \)
(c) \( \mathrm{x}-\tan ^{-1}\left(\frac{y}{x}\right)=\mathrm{c} \)
(d) none of these
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