Due to \( 10 \mathrm{~A} \) of current flowing in a circular coil of 10 \( \mathrm{cm} \) radius...
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0Due to \( 10 \mathrm{~A} \) of current flowing in a circular coil of 10 \( \mathrm{cm} \) radius, the magnetic field produced at its centre is \( 3.14 \times 10^{-3} \mathrm{~Wb} / \mathrm{m}^{2} \). The number of turns in the coil will be
(A) 5000
(B) 100
(C) 50
(D) 25
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