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Targ (1980)

Duration: 2:26

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Electrons with de-Broglie wavelength \( \lambda \) fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is
(a) \( \lambda_{0}=\frac{2 m c \lambda^{2}}{h} \)
(b) \( \lambda_{0}=\frac{2 h}{m c} \)
(c) \( \lambda_{0}=\frac{2 m^{2} c^{2} \lambda^{3}}{h^{2}} \)
(d) \( \lambda_{0}=\lambda \)
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