Energy needed to remove a neutron from the nucleus of the calcium i... VIDEO
Energy needed to remove a neutron from the nucleus of the calcium isotope \( { }_{20}^{42} \mathrm{Ca} \) Energy needed to remove a proton from this nucleus
(c) Why are these energies different?
Atomic masses of \( { }_{20}^{41} \mathrm{Ca} \) and \( { }_{20}^{42} \mathrm{Ca} \) are \( 40.962278 \mathrm{u} \) and \( 41.958622 \) u respectively.
Atomic mass of \( { }_{19}^{41} \mathrm{~K} \) is \( 40.961825 \mathrm{u} \), Mass of Proton is \( 1.007826 \mathrm{u} \)
\( \mathrm{P} \)
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