f = std::forward in lambda capture, what does it mean?

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f = std::forward in lambda capture, what does it mean?
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(stackoverflow.com/users/3834459/dean)Dean |
(stackoverflow.com/users/4342498/nathanoliver)NathanOliver |
(stackoverflow.com/users/16264289/jonathan-s)Jonathan S. |
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forwarding-reference metaprogramming perfect-forwarding c++







Tags:
forwarding-reference
metaprogramming
perfect-forwarding
c++