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Figure show a uniform block of mass \( m=\sqrt{\frac{3}{13}} \mathrm{~kg} \) having square base and equilateral triangular cross section placed at the edge of the floor of a truck which is under constant
P acceleration \( a=\frac{g \sqrt{3}}{4} \mathrm{~m} / \mathrm{s}^{2} \) to the right. A horizontal force on the apex of the triangle \( F \) is just enough to just tilt the block. Find the force (in newton) on the block at point \( A \) where the block is in contact with the step edge when \( F \) is applied. (Take \( g=10 \mathrm{~m} / \mathrm{s}^{2} \) )
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