Figure shows a part of a bigger circuit. The capacity across the capacitor at the as follows: \[...
Channel:
Subscribers:
445,000
Published on ● Video Link: https://www.youtube.com/watch?v=vYHpHxpoVIc
0Figure shows a part of a bigger circuit. The capacity across the capacitor at the as follows:
\[
\begin{array}{l}
\text { as follows: } \\
\qquad \frac{d V}{d t}=2 \mathrm{~V} \mathrm{~s}^{-1}, \frac{d^{2} V}{d t^{2}}=\frac{1}{2} \mathrm{~V} \mathrm{~s}^{-2}
\end{array}
\]
The current in the \( 4 \Omega \) resistor is decreasing at the rate of 1 \( \mathrm{mA} \mathrm{s}{ }^{-1} \). What is the potential difference (in \( \mathrm{mV} \) ) across the inductor at this moment?
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live
Other Videos By PW Solutions
Tags:
pw