Figure shows a potentiometer with a cell of emf \( 2.0 \mathrm{~V} \) and internal resistance \(...
0Figure shows a potentiometer with a cell of emf \( 2.0 \mathrm{~V} \) and internal resistance \( 0.04 \Omega \) maintaining a potential drop across the potentiometer wire \( A B \). A standard cell which maintains a constant emf of \( 1.02 \mathrm{~V} \) (for very moderate currents up to a few ampere) gives a balance point of \( 67.3 \mathrm{~cm} \) length of the wire. To ensure very low currents drawn from the standard cell, a very high resistance of \( 600 \mathrm{k} \Omega \) is put in series with it which is shorted close to the balance point. The standard cell is then replaced by a cell of unknown emf \( \mathrm{E} \) and the balance point found similarly turns out to be at \( 82.3 \mathrm{~cm} \) length of the wire.
Would the method work in the above situation if the driver cell of the potentiometer had an emf of \( 1.0 \mathrm{~V} \) instead of \( 2.0 \mathrm{~V} \) ?
PD
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