Find a three-digit number whose consecutive digits form a \( \mathrm{GP}\). If we subtract \(792....

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Question Find a three-digit number whose consecutive digits form a \( \mathrm{GP}\). If we subtract \(792\) from this number, we get a number consisting of the same digits written in the reverse order. Now, if we increase the second digit of the required number by \(2\), then the resulting digits will form an \( \mathrm{AP}\).
(A) \(319\)
(B) \(913\)
(C) \(931\)
(D) \(391\)šŸ“²PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live




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