Find Subarray With Bitwise AND Closest to K | Sliding Window | Leetcode 3171 | codestorywithMIK

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Published on June 4, 2024 12:00:00 AM ● Video Link: https://www.youtube.com/watch?v=BWBKtU8Euno

Duration: 1:00:23

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This is the 22nd Video of our Playlist "Sliding Window : Popular Interview Problems" by codestorywithMIK

In this video we will try to solve a good practice String problem : Find Subarray With Bitwise AND Closest to K | Sliding Window | Detailed Explanation | Leetcode 3171 | codestorywithMIK

I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.

Problem Name : Find Subarray With Bitwise AND Closest to K | Sliding Window | Detailed Explanation | Leetcode 3171 | codestorywithMIK
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My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Intervie...
Leetcode Link : https://leetcode.com/problems/find-su...


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Summary :
The approach finds the minimum absolute difference between a target value k and the bitwise AND of any contiguous subarray of nums using a sliding window and bit manipulation:

Bit Frequency Tracking: Maintain an array freqBits to track how many numbers in the current window have each bit set to 1.

Sliding Window: Use two pointers, i and j, to represent the window. Extend the window by moving j and shrink it by moving i.

Update and Compare:

Update freqBits and compute the bitwise AND (windowAnd) for the current window.
Calculate the absolute difference between k and windowAnd, updating the result if this difference is smaller.
Early Termination: If windowAnd equals k, return 0 immediately since this is the best possible result.

This approach efficiently finds the minimum difference by leveraging bit manipulation and the sliding window technique.


✨ Timelines✨
00:00 - Introduction

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